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jeka57 [31]
2 years ago
10

Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed?

Mathematics
2 answers:
kykrilka [37]2 years ago
5 0

we will select each options and find zeros

(a)

g(x)=x^2-4x-21

for finding x-intercept , we can set g(x)=0

and then we can solve for x

g(x)=x^2-4x-21=0

now, we can factor it

(x-7)(x+3)=0

we get

x=7,x=-3

so, this is TRUE

(b)

g(x)=(x-3)(x+7)

we can set it to 0

and then we can solve for x

g(x)=(x-3)(x+7)=0

we get

x=3,x=-7

so, this is FALSE

(c)

g(x)=3x^2-12x-63

we can set it to 0

and then we can solve for x

g(x)=3x^2-12x-63 =0

3(x^2-4x-21) =0

3(x-7)(x+3) =0

x=-3,x=7

so, this is TRUE

(d)

g(x)=-(x+3)(x-7)

now, we can set it to 0

and then we can solve for x

g(x)=-(x+3)(x-7)=0

x=-3,x=7

so, this is TRUE

(e)

we have

g(x)=x^2+4x-21

now, we can set it to 0

and then we can solve for x

g(x)=x^2+4x-21=0

(x+7)(x-3)=0

x=-7,x=3

so, this is FALSE

konstantin123 [22]2 years ago
4 0

Answer:A.  C. D

Step-by-step explanation:

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How do I do this? Please explain in detail.
umka2103 [35]
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
8 0
3 years ago
Read 2 more answers
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