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Sergeu [11.5K]
3 years ago
9

3ab (2ab + 2a -b )-2a (2ab -2b +a )

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0
<span> a • (6ab2 + 2ab - 2a - 3b2 + 4b) </span>

Step by step solution :<span>Step  1  : 
</span><span>Equation at the end of step  1  :</span> (3ab • (2ab + 2a - b)) - 2a • (2ab + a - 2b) <span>Step  2  :</span><span>Equation at the end of step  2  :</span> 3ab • (2ab + 2a - b) - 2a • (2ab + a - 2b) <span>Step  3  :</span><span>Step  4  :</span>Pulling out like terms :

<span> 4.1 </span>    Pull out like factors :

  <span> 6a2b2 + 2a2b - 2a2 - 3ab2 + 4ab</span>  = 

 <span> a • (6ab2 + 2ab - 2a - 3b2 + 4b)</span> 

Final result :<span> a • (6ab2 + 2ab - 2a - 3b2 + 4b)</span>
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Following are the solution to the given question:

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For question 2:

Calculating the speed between B and C:

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In this the speed between A and B is the double to speed between B and C.

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In triangle ΔABC, ∠C is a right angle and CD is the height to AB . Find the angles in ΔCBD and ΔCAD if: Chapter Reference a m∠A
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Answer:

Given A triangle ABC in which

 ∠C =90°,∠A=20° and CD ⊥ AB.

In Δ ABC

⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]

⇒20° + ∠B + 90°=180°

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∠B =180° -110°

∠B = 70°

In Δ B DC

∠BDC =90°,∠B =70°,∠BC D=?

∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]

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In Δ AC D

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