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Mazyrski [523]
3 years ago
12

Find the equation of the plane through the point p=(2,3,4)p=(2,3,4) and parallel to the plane 5y−5x−5z=4.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0
Find plane Π parallel to 5y-5x-5z=4 containing point p=(2,3,4) 

Any plane parallel to 5y-5x-5z=4 has the form 5y-5x-5z=k, or on simplification, y-x-z=k.

Since p lies in the plane, the coordinates of p must satisfy y-x-z=k, or
k=3-2-4=-3
=>
π : y-x-z=-3
equivalently, 
π : 5y-5x-5z=-15

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Answer:

x = 5

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Step-by-step explanation:

y varies directly as x

y = kx

and inversely as z

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Putting in the numbers in the first line of the table, we can solve for k

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Divide by 25

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Now we can fill in the table

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4 years ago
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