1 = 100%
1 % = 1/100 = 0.01
0.6 % = 0.6 · 0.01 = 0.006
Answer: C ) 0.006
I believe its 50 because 0.35x50=17.5 (35%=0.35)
64% of 75 = 64/100 x 75 = 48 <==== answer
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Answer:
Step-by-step explanation:
Remark
You have 2 points to solve the equation y = mx + b. After finding m, use either of the points to find b.
Formula
y = mx + b
m = (y2 - y1)/(x2 - x1)
Solution
- y2 = 13
- y1 = 5
- x2 = 0
- x1 = 24
m = (13 - 5)/(0 - 24)
m = 8 / - 24
m = - 1/3
y = mx + b
y = -1/3 x + b
Use (0,13) as the point.
13 = -1/3 * 0 + b
13 = b
The y intercept = (0,13)