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777dan777 [17]
3 years ago
9

28 - 2 (5a - 3) = 47

Mathematics
1 answer:
Alex787 [66]3 years ago
5 0

Answer: a=-1.3

Step-by-step explanation:

1) Reorder the terms: 28 + (-3 * -2 + 5a * -2) = 47

28 + (6 + -10a) = 47

2) Solving: 34 + -10a = 47

3) Add -34 to each side of the equation: 34 + -34 + -10a = 47 + -34

4) Combine like terms: 34 + -34 = 0: 0 + -10a = 47 + -34

-10a = 47 + -34

5) Combine like terms: 47 + -34 = 13: -10a = 13

6) Divide each side by -10: a = -1.3

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410 - 25 = 386

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3 years ago
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the perimeter of a square is equal to the perimeter of an equilateral triangle the length of a side of the square is given by th
diamong [38]

Answer:

x = 3

Step-by-step explanation:

We are told that the length of a side of the square is x.

Now, perimeter of square = 4 × side length

Perimeter of square = 4x

Also,we are told that the triangle is equilateral and a side is (x + 1).

Thus, perimeter of triangle = 3(x + 1)

Since we are told that the perimeter of the square is equal to that of the equilateral triangle. Thus;

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Subtract 3x from both sides to get;

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3 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

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=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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Step-by-step explanation:

you start by finding the prime factorization of the number

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Answer:

where is the expression??

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