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ivann1987 [24]
3 years ago
12

Plzz Help !!!! What í the equation of (2x+y)^3 ???

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0
If you are talking about the binomial being expanded then it would be:

8x^3 + 12x^2y + 6xy^2 + y^3

The y in the second term is not part of the exponent

And since you are raising the binomial to the third, you would be using the third row of Pascal's triangle.

Hope this helped!
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A parking lot is 100 yards long what is the length off 3/4if the parking lot
andriy [413]
I think you mean:
A parking lot is 100 yards long. What is the length of 3/4 of the parking lot?

3/4 * 100            Mathematical Expression.

3/1 * 25              Simplify.

75                       Multiply.

Final Answer: 75 yards long
4 0
3 years ago
1797 is 31% of a number. What number?
abruzzese [7]
You should
1797/g = 31/100
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g= 5796.77
8 0
3 years ago
The set of negative integers less than 0 but greater than -10?<br>help me please ​
Len [333]
S.S{-1 ,-2,-3,-4,-5,-6,-7,-8,-9}

Its only asking numbers less than zero but greater than-10 so 0 and -10 will not be included. Only numbers in bn
3 0
3 years ago
Read 2 more answers
What are the roots of the quadratic equation below?<br> x2 + 2x= -5
muminat

Answer:

No real root.

Complex roots:

x = -1 \pm 2i

Step-by-step explanation:

x^2 + 2x = -5

x^2 + 2x + 5 = 0

There are no two integers whose product is 5 and whose sum is 2, so this trinomial is not factorable. We can use the quadratic formula.

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-2 \pm \sqrt{2^2 - 4(1)(5)}}{2(1)}

x = \dfrac{-2 \pm \sqrt{4 - 20}}{2}

x = \dfrac{-2 \pm \sqrt{-16}}{2}

Since we have a square root of a negative number, there are no real roots. If you have learned complex numbers, then we can continue.

x = \dfrac{-2 \pm 4i}{2}

x = -1 \pm 2i

7 0
3 years ago
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3x to the second power + 4x -7
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6 0
2 years ago
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