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3 years ago

Plzz Help !!!! What í the equation of (2x+y)^3 ???

1 answer:

4 0

If you are talking about the binomial being expanded then it would be:

8x^3 + 12x^2y + 6xy^2 + y^3

The y in the second term is not part of the exponent

And since you are raising the binomial to the third, you would be using the third row of Pascal's triangle.

Hope this helped!

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3x+8 if x=2 <br> 15 <br> 13<br> 16<br> 14

grandymaker [24]

Answer:

Step-by-step explanation:

3*2+8

=14

6 0

3 years ago

What is the constant of the variation for the inverse variation?

Alisiya [41]

Answer:

2nd possible answer is the correct one; the const. of var. is 1/3.

Step-by-step explanation:

xy = 1/3 can be rewritten in inverse variation format: Divide both sides by x to isolate y. Then y = (1/3)(1/x). The constant of (inverse) variation is 1/3.

4 0

3 years ago

Which function has an inverse that is a function?

statuscvo [17]

Answer:

i aint never seen two pretty bestfriends

Step-by-step explanation:

3 0

3 years ago

How do you solve the system of equations 4 x − 2 y = 1 and -4 + 4 y = -2

Dmitrij [34]

Answer: y= -2 - 1/2

Step-by-step explanation:

-4x -2y = 1

+4x +4x

-2y = 4x + 1

/-2 /-2 /-2

y= -2 - 1/2

I think, i may be incorrect but the verbal explanation is; -4x is needed to be moved so you add 4x to both sides and 4x cancels out on the left which leaves -2y on the left (when it was moved "x" is always first). then divide all numbers by -2 to get y by itself. this gives you y= -2 - 1/2 if my calculations are correct.

4 0

4 years ago

The Department of Commerce in a particular state has determined that the number of small businesses that declare bankruptcy per

skad [1K]

Answer:

B) 0.1487

Step-by-step explanation:

Let $X$ be the discrete random variable that represents the number of events observed over a given time period. If $X$ follows a Poisson distribution, then the probability of observing $k$ events over the time period is:

$P(X=k)=\frac{\lambda^{k} *e^{-\lambda} }{k!}$

Where:

$\lambda=Mean\\k=number\hspace{3}of\hspace{3}events\\e=Euler's\hspace{3}number$

So, the probability that exactly 5 bankruptcies occur next month is:

$P(X=5)=\frac{6.4^{5} *e^{-6.4} }{5!} =\frac{17.84083537}{120} =0.1486736281\approx0.1487$

4 0

3 years ago