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kap26 [50]
3 years ago
9

Determine the common ratio and find the next three terms of the geometric sequence

Mathematics
2 answers:
viva [34]3 years ago
7 0

Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

murzikaleks [220]3 years ago
3 0

Answer:

Option (b) is correct.

The three terms of the GP are 12,12\sqrt{2},24 with common ratio \sqrt{2}

Step-by-step explanation:

Consider the given geometric sequence 3\sqrt{2},6,6\sqrt{2}......

Geometric sequence is a sequence of numbers where each term  is find by multiplying the previous one by a fixed number called the common ratio (r).

a,\ ar,\ ar^{2},\ ar^{3},\ ar^{4},\ \ldots

Consider the first two terms of the given GP.

a=3\sqrt{2},ar=6 thus r can be find by dividing ar by a,

thus the common ratio is r=\frac{6}{3\sqrt{2}}=\sqrt{2}

Now we have to find the next three terms of GP . so multiply r in given last term to obtain next three terms , we get ,

6\sqrt{2} \times \sqrt{2}=6\times 2= 12 \\\\\\12 \times \sqrt{2}= 12\sqrt{2}\\\\\\\12\sqrt{2} \times\sqrt{2}=24

Thus, the three terms of the GP are 12,12\sqrt{2},24 with common ratio \sqrt{2}.

Option (b) is correct.




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Joachim wants to win the giant monkey at the carnival game. To do so, he'll need to roll two ones with a single toss of a pair o
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12. Algebra There are 92 students in the third and fourth grades at Johnsonville Elementary. Of these, 47 are in fourth grade. W
Fudgin [204]

x + 47 = 92.   <--- x represents the number of 3rd graders

x +47-47 = 92-47

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4 0
3 years ago
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Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

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3 years ago
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10. 105 in
11.50 m
Explanation:
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