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ikadub [295]
4 years ago
13

a. On a hiking trip Bob and his two friends hiked 15 miles the first day, 10 miles on the second and 7 miles on the third day. I

f they walked a total of 60 miles over a 5 day trip and did not walk more than 18 miles on any one day, how many miles could they have walked each of the last two days? b. If they hiked at a top speed of 6 miles per hour on flat terrain, but had to slow down when climbing hills could they have have made the trip in a single 10 hour day of sunshine? Support your answer.
Mathematics
1 answer:
Len [333]4 years ago
7 0

Answer: A. 14 miles each day.


Step-by-step explanation:


Day 1 : 15 miles

Day 2 : 10 miles

Day 3 : 7 miles


15 + 10 + 7 = 32 miles


60 - 32 = 28 miles


2 days left


28/2 = 14


14 is less than 18



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Answer:

c) 5.39

Step-by-step explanation:

The digit that is in the hundredths place is the 8. (The hundredths are two digits to the right of the point).

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Sherman goes golfing every 6th day. and Brad goes golfing every 7th day.
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Find the least common multiple of each number:

6, 12, 18, 24, 30, 36, 42

7, 14, 21, 28, 35, 42

The least common multiple is 42, which means every 42 days they will golf on the same day.

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Which expression shows 27 + 36 as the product of their greatest common factor and the sum of two whole numbers with no common fa
Diano4ka-milaya [45]
I believed there is a typo error in the choices. Below I assume that the correct choices:

<span>A. 9 (3+4)
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The answer is letter A which is 9 (3+4) the greatest common denominator of 27 and 36 is 9. The factor of 27 is 9 and 3 while for 36 is 9 and 4. To check the answer you need to solve 9 (3+4) which is 63 while 27 + 36 is also 63. 
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Three angles are in the ratio 2 : 3 : 5 The smallest angle is 50 degrees Work out the sizes of the other two angles
Oxana [17]
Since the smallest angle is 50 degrees, then divide 50 by 2 (because of the ratio) and you get 25. Now you can multiply 25 by 3 and 25 by 5 to get the remaining angles which would be 75 degrees and 125 degrees.
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Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan
Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation

1) For x = 3

z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5

For x = 6

z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67

For x = 70

z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19

For x = 12

z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5)  x = 90

z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6)  For x = 10

z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25

For x = 20

z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7)  For x = 7

z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67

For x = 9

z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33

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8)  For x = 40

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For x = 47

z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9)  x = 120

z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0
3 years ago
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