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german
3 years ago
12

What is the truth value for the following conditional statement? p: true q: false p → q T F → F T F → T F T → T F F → T

Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0

I'm pretty sure it's TF->T

Daniel [21]3 years ago
5 0

the answer would be  true

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Vadim26 [7]

Answer:

Am I missing something to this question?

As pictured, the answer is 12 7/9ths.

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Dos numeros que multiplicados den 126 y restados den 10
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2 years ago
simplify the exponential expression completely. pleeeease help me!!!!! thank you so so so much!!! *will give brainliest*
Marrrta [24]

Answer:

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Step-by-step explanation:

8 0
2 years ago
A cube made out of lead has a mass of 12 grams. A side of the cube has length 1 cm. What would be the mass of the cube whose sid
Ulleksa [173]

Answer:

<h3><em><u>The mass of a lead cube whose </u></em><em><u>side </u></em><em><u>have length 1.5 cm is 40.5 </u></em><em><u>grams</u></em></h3>

Step-by-step explanation:

<u>1. Let's review the information given to</u>

<u>1. Let's review the information given tous to answer the question correctly:</u>

<u>1. Let's review the information given tous to answer the question correctly:Mass of the cube made out of lead</u> = 12

= 12grams

Side of the cube <em>= 1 cm</em>

2. <em><u>What would be the mass of a lead</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let's</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube and</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube andthen its density, this way:</u></em>

<h3>Volume = Height* Width * Length</h3><h3>Volume=1*1*1</h3><h3>Volume =1 cm</h3>

Let's recall the formula of the density:

Density Mass/Volume, therefore:

Density of the lead <em><u>= 12/1= 12 gr/</u></em><em><u>cm</u></em>

<em><u>Now, let's calculate the volume of the</u></em>

<em><u>Now, let's calculate the volume of thesecond cube:</u></em>

<h3><em>Volume = Height Width Length</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5Volume =3.375 cm3</em></h3>

<u>Finally, let's calculate the mass, using</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we already</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we alreadyknow:</u>

<h3>Density = Mass/Volume</h3><h3><em>12 Mass/3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375Mass = 40.5 gramss</em></h3>
8 0
2 years ago
A diving board is 10 feet above the surface of the water. At time t = 0, the board propels Chris upward at a rate of 12 feet per
Art [367]

Answer:

Chris will take 0.75 seconds to return to his starting height of 10 feet.

Step-by-step explanation:

Let the height of Chris be represented by h(t) = -16\cdot t^{2}+12\cdot t +10, where h(t) is the height in feet and t, the time in seconds. First, we equalize the formula to a height of 10 feet and simplify the resulting expression, that is:

-16\cdot t^{2}+12\cdot t +10 = 10

-16\cdot t^{2}+12\cdot t = 0

Then, we simplify the expression by algebraic means:

-16\cdot t\cdot \left(t-\frac{3}{4} \right) = 0

Roots of the polynomial are, respectively:

t = 0\,s\,\lor \,t = 0.75\,s

First root represents the initial height of Chris, whereas the second one represents the instant when Christ returns to the same height above the surface of the water. Hence, Chris will take 0.75 seconds to return to his starting height of 10 feet.

5 0
2 years ago
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