Answer:
6° and acute angle
you watch the clock or find a clock, in right angle there 90° or 3 o'clock, if you want to understand it, try to count the the minute from 12 to 3 in the clock, if you count it then you see the are there is 15 minutes, then the 90° divide the number of minute which is 15, the answer is 6°. and then the answer of the next question is acute angle it is because the hour hand of the clock travels in 1 minute, it means every 1minute there are 6°, and 6° is less than 90° that why it's acute angle.
Answer:
605 rupees
Step-by-step explanation:
add the parts of the ratio 3 + 4 = 7
divide the number of notes by 7 to find one part of the ratio
= 11 ← 1 part of the ratio
3 parts = 3 × 11 = 33 ← number of 5 rupee notes
4 parts = 4 × 11 = 44 ← number of 10 rupee notes
Amount of money = (33 × 5 ) + (44 × 10) = 165 + 440 = 605 rupees
Answer:
∆ABC ≅ ∆EDF by the SAS Congruence Theorem.
Step-by-step explanation:
<A ≅ <E,
Side length AC ≅ Side length EF
Side length AB ≅ Side length ED,
Thus, this implies that an included angle and two sides of one triangle are congruent to an included angle and 2 corresponding side lengths of the other triangle.
Therefore, we would conclude that:
∆ABC ≅ ∆EDF by the SAS Congruence Theorem.
Answer:
Step-by-step explanation:
We are given the following in the question:
We have to convert this equation into logarithmic equation.
Relation between exponent and logarithmic:
- Logarithmic functions are the inverses of exponential functions.
- The logarithmic function
is defined to be equivalent to the exponential equation 
For the given expression a = e, y = 1.5 and x = 4.4816...
We can express them as:
Answer:
1a) UCL = 14.2
LCL = 10.9
b) UCL = 15.63
LCL = 9.37
c) UCL = 16.48
LCL = 8.52
2) The difference between the limits falls close together as n increases
and the difference between the limits falls farther away from 12.5
Step-by-step explanation:
mean ( μ ) = 12.5
std ( б ) = 1.1
UCL = μ + ( n - 1 ) б / √n
LCL = μ - ( n - 1 ) б / √n
1) a) Given n = 4
UCL = 12.5 + ( 3 ) * 1.1 / 2
= 12.5 + 3.3/2 = 14.15 ≈ 14.2
LCL = 12.5 - 3.3/2 = 10.85 ≈ 10.9
b) Given n = 10
UCL = 12.5 + ( 9 ) * 1.1 /√10
= 12.5 + 3.13 = 15.63
LCL = 12.5 - 3.13 = 9.37
c) Given n = 15
UCL = 12.5 + 14 * 1.1 / √15
= 12.5 + 3.98 = 16.48
LCL = 12.5 - 3.98 = 8.52
2) As the sample size increases the difference between the limits of the control chart decreases
Hence the difference falls close together as n increases
and the difference between the limits falls farther away from 12.5
