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melamori03 [73]

3 years ago

12

Rajesh wakes up at 7:00 a.m. and takes a walk for half an hour. He then spends 30 minutes bathing and eating breakfast. After wa

tching the morning news on TV for a while, Rajesh leaves for school at 9:30 a.m. How many hours does Rajesh spend watching the news?

2 answers:

Darina [25.2K]3 years ago

7 0

2 ...........................

tatyana61 [14]3 years ago

5 0

Rajesh spent an hour watching the news.

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ohaa [14]

Answer:

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What is the percent?

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Step-by-step explanation:

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2 years ago

Nathan is collecting aluminum cans for charity. One empty 355 ml can weighs about 17 g. It takes 59 cans to get about 1 kg of 10

Jlenok [28]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Tan 3A in terms of tan

Zanzabum

Here's the sum rule for the tangent function:

$\tan(a+b)=\dfrac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}$

In the special case a=b, this becomes the double angle formula:

$\tan(a+a)=\tan(2a)=\dfrac{\tan(a)+\tan(a)}{1-\tan(a)\tan(a)}=\dfrac{2\tan(a)}{1-\tan^2(a)}$

In your case, you case use the sum rule once:

$\tan(3a)=\tan(2a+a)=\dfrac{\tan(2a)+\tan(a)}{1-\tan(2a)\tan(a)}$

And use it again, in the special case of the double angle:

$\dfrac{\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a)}{1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a)}$

We can obvisouly simplify this expression a lot: let's deal with the numerator and denominator separately: the numerator is

$\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a) = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}$

and the denominator is

$1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a) = \dfrac{1-\tan^2(a)-2\tan^2(a)}{1-\tan^2(a)} = \dfrac{1-3\tan^2(a)}{1-\tan^2(a)}$

So, the fraction is

$\dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}\cdot \dfrac{1-\tan^2(a)}{1-3\tan^2(a)} = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-3\tan^2(a)}$

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3 years ago

Find the range of the graphed function.

sergij07 [2.7K]

Answer:

<h2>Hey , option D is correct..</h2>

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2 years ago