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Deffense [45]
3 years ago
12

Solve for x -9<4x+3<27 enter your answer as one inequality in the box

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

If a< c< b then a<c and c<b

Separate the equation into 2 separate ones and solve them:

X-9 < 4x +3

Subtract 3 from both sides:

X-12 < 4x

Subtract x from both sides:

-12< 3x

Divide both sides by 3:

X > -4

4x+3 < 27

Subtract 3 from both sides

4x < 24

Divide both sides by 4

X <6

Combine to get one inequality:

-4<x<6

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Find the slope of the line running<br> through these two points (-4,5) and (8,-3)
Artemon [7]

Answer:

The slope is

\frac{-3-5}{8-(-4)} =\frac{-8}{8+4} =\frac{-8}{12} =-\frac{2}{3}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Joel spends 272727 more minutes playing soccer after school on Tuesday than he did on Monday. He still exercises for a total of
Nookie1986 [14]

Joel spent 72.5% of his time exercising after playing soccer on Tuesda

<h3>How to determine the percentage?</h3>

The given parameters are

Minutes spent on Tuesday = 27 more minutes than Monday

Total minutes spend = 60

This means that

Tuesday = Monday + 27

Monday + Tuesday = 60

Make Monday the subject in Tuesday = Monday + 27

Monday = Tuesday - 27

Substitute Monday = Tuesday - 27 in Monday + Tuesday = 60

Tuesday - 27 + Tuesday = 60

Evaluate

2 * Tuesday = 87

Divide by 2

Tuesday = 43.5

The percentage of time spent exercising on Tuesday is then calculated as

Percentage = 43.5/60 * 100%

Evaluate the expression

Percentage = 72.5%

Hence, Joel spent 72.5% of his time exercising after playing soccer on Tuesday

Read more about percentages at:

brainly.com/question/843074

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6 0
1 year ago
Please help me and give me correct answer
snow_lady [41]
The house is in the coordinate plane is (4.5, -1.5).

Thats all I know, hope that helped for now.

~Sam
3 0
2 years ago
HELP THIS IS HARD SOMEONE pls
IrinaK [193]

Answer:

3rd option

Step-by-step explanation:

Since the centre of dilatation is at the origin then multiply the coordinates by \frac{1}{3}

K (- 3, 9 ) → K' (- 3(\frac{1}{3} ), 9(\frac{1}{3} ) ) → K' (- 1, 3 )

L (- 9, 0 ) → L' (- 9(\frac{1}{3} ), 0 (\frac{1}{3} ) ) → L' (- 3, 0 )

M (2, - 8 ) → M' (2 (\frac{1}{3} ), - 8 (\frac{1}{3} ) ) → M' ( \frac{2}{3} , - \frac{8}{3} )

N (6, 4 ) → N' (6 (\frac{1}{3} ) , 4 (\frac{1}{3} ) ) → N' ( 2, \frac{4}{3} )

7 0
2 years ago
Tony has a rectangular yard he would like to fence. He knows the length of his yard is 3x3+4x2−6x and the width of the yard is 2
Step2247 [10]

Answer:

P = 6x³ + 12x² - 18x + 8

Step-by-step explanation:

Given that:

Length = 3x3+4x2−6x

Width = 2x2−3x+4

The length of fencing needed will be :

Perimeter of rectangle (P) = 2( Length + Width)

P = 2[ (3x3+4x2−6x) + (2x2−3x+4)]

P = 2 (3x³+ (4x² + 2x²) + (-6x - 3x) + 4)

P = 2(3x³ + 6x² - 9x + 4)

P = 6x³ + 12x² - 18x + 8

6 0
2 years ago
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