Answer:
4,500 x 5 = 22,500
4,500 divided by 5 = 900
4,500 plus 5 = 4,505
4,500 minus 5 = 4,495
Step-by-step explanation:
it is either one of those that u have to choose from good luck
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
The product of 289 and 7 is 2023
So 2023 is in between the pair of numbers 2022 and 2024
or even in between the pair of numbers 2020 and 2025. You can make a lot of pairs, haha.
The answer to that complicated question my good sir or mam is 5
Answer: y = 3x - 2
Step-by-step explanation:
slope intercept: y = mx + b, where m is the slope and b is the y-intercept.
Thus, because you already know the slope, you can simplify the equation to
y = 3x + b.
Then plug in the provided point to get, 4 = 3(2) + b
4 = 6 + b
-2 = b
Thus,
y = 3x - 2
Hope it helps :)
