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mash [69]
3 years ago
10

Multiply: k+3 4k−2 ×(12 k 2 +2k − 4)

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0
K+3 * 4k=12k
2(12k * 2 + 2k - 4) = 2(26k - 4)
= k + 12k - 2 (26k - 4)
- 2 (26k - 4) : -52k+8
=k + 12k - 52k = -39k
FINAL ANSWER = -39k + 8
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Karla makes paper airplanes. Today, it takes her 32 min to make 16 paper airplanes.
Pavel [41]

Answer:

48/b

Step-by-step explanation:

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7 0
3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME???
dedylja [7]

Answer:

No.

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y=1,3,5,7 or 9

8 0
3 years ago
15. You want to wrap a paperweight shaped like the
Bond [772]

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4 0
3 years ago
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guajiro [1.7K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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