#4) 1/6
#5) 1/2
#6) 4/15
#7) 8/15
#8) 11/15
#9) 12
#10) 15
#11) 112
Explanation
#4) There is one section marked 5 out of 6 sections.
#5) There are three odd-numbered sections out of 6 sections.
#6) 2 blue were tossed 4 times out of 15 tosses.
#7) 1 blue and 1 pink were tossed 8 ties out of 15 tosses.
#8) All blue was tossed 4 times out of 15; this means that all blue was not tossed 15-4=11 times out of 15.
#9) There are 4 choices for location and 3 choices for transportation; 4(3) = 12.
#10) There are 3 choices for level and 5 choices for character; 3(5) = 15.
#11) Since 30% are rock, 100%-30% = 70% are not rock. 70% = 70/100 = 0.7; 0.7*160 = 112.
Answer: SAS
Step-by-step explanation:
There is an angle B or D and the sides being the 26, 21, and 32! (Sorry if I get it wrong)
Answer:
i realy dont known dude haaaaaaaahaaahahahah
Step-by-step explanation:
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
