8-9n=15 I believe
At least I hope
Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]
Answer:
Considering the given equation 
And the ordered pairs in the format 
I don't know if it is log of base 3 or 10, but I will assume it is 3.
For 


So the ordered pair will be 
For 


So the ordered pair will be 
For 


So the ordered pair will be 
For 


So the ordered pair will be 
For 


So the ordered pair will be 
For 


So the ordered pair will be 
Answer: No, the money won't be enough to buy the car
Step-by-step explanation:
you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.
The principal amount, p = 300
He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So
n = 4
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for a total of 24 months. This is equivalent to 2 years. So
n = 2
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount that would be compounded at the end of n years.
A = 300(1 + (0.04/4)/4)^4×2
A = 300(1 + 0.01)^8
A = 300(1.01)^8
A = $324.857
The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car
Answer:
see explanation
Step-by-step explanation:
Her error is in squaring (2y)²
She has (2y)² = 2y²
when it should be 2y × 2y = 4y²
Then
(2y)² = 6² + 8²
4y² = 36 + 64
4y² = 100 ( divide both sides by 4 )
y² = 25 ( take square root of both sides )
y =
= 5
Four and Eleven Hundredth