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Anni [7]
3 years ago
10

8 less than the product of 9 and a number is 15

Mathematics
2 answers:
Finger [1]3 years ago
6 0

9n-8=15

Product of n and 9 is 9n

Subtract 8 less than that.

Shkiper50 [21]3 years ago
4 0
8-9n=15 I believe
At least I hope
You might be interested in
Increase 3000 by 5.4%
katen-ka-za [31]
------------------------------------
Original Number
------------------------------------
3000

------------------------------------
Increase
------------------------------------
5.4% of 3000
= 0.054 x 3000
= 162

------------------------------------
New Total
------------------------------------
3000 + 162 = 3162

------------------------------------
Answer: 3162
------------------------------------
6 0
3 years ago
Suppose the initial height of a Pumpkin is 12 feet and the pumpkin is being launched with a velocity of 61 feet per second. Use
iogann1982 [59]
<h2>Hello!</h2>

The answer is:

The maximum height before landing will be 69.7804 feet.

<h2>Why?</h2>

Since there is no information about the angle of the launch, we can safely assume that it's launched vertically.

So, we can calculate the maximum height of the pumpkin using the following formulas:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

v=vo-gt

Where,

y, is the final height

y_o, is the initial height

g, is the acceleration of gravity , and it's equal to:

g=32.2\frac{ft}{s^{2} }

t, is the time.

Now, we are given the following information:

y_{o}=12ft\\\\v=61\frac{ft}{s}

Then, to calculate the maximum height, we must remember that at the maximum height, the speed tends to 0, so, calculating we have:

Time calculation,

We need to use the following equation,

v=vo-gt

So, substituting we have:

v=61\frac{ft}{s}-32.2\frac{ft}{s^{2}}*t\\\\-61\frac{ft}{s}=-32.2\frac{ft}{s^{2}}*t\\\\t=\frac{-61{ft}{s}}{-32.2\frac{ft}{s^{2}}}=1.8944s

We know that it will take 1.8944 seconds to the pumpkin to reach its maximum height.

Maximum height calculation,

Now, calculating the maximum height, we need to use the following equation:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

Substituting and calculating, we have:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}\\\\y_{max}=12ft+115.5584ft-16.1\frac{ft}{s^{2}}*(3.5887s^{2})\\\\y_{max}=127.5584ft-57.7780ft=69.7804ft

Hence, we have that the maximum height before the landing will be 69.7804 feet.

Have a nice day!

3 0
3 years ago
Samantha works part time at a store where she earns $462.30 each month
VARVARA [1.3K]

Answer:

y=462.30m

Step-by-step explanation:


7 0
3 years ago
Which is greater 5/8 or 7/16
melamori03 [73]

Answer:

5/8=0.62

7/16=0.43

So 5/8 is greater

6 0
2 years ago
Use the Quadratic Formula to solve the equation. -2x^2 - 5x + 5 = 0
olga2289 [7]
The answer is going to be in the picture because trying to make fractions with this is too difficult. :D

7 0
3 years ago
Read 2 more answers
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