Solution:
<u>Note that:</u>
- Area of trapezoid = Area of triangle + Area of square = 575 m²
- Area of triangle = 32.5 m²
- Area of square = s²
<u>Finding the area of the square:</u>
- 32.5 + Area of square = 575 m²
- => Area of square = 575 - 32.5
- => Area of square = 542.5
- => s² = 542.5
- => s = √542.5 ≈ 23.29
The length of the square is 23.29 meters.
Answer:
Valid
Step-by-step explanation:
3(x-4)=x+4 <em>Given</em>
3x-12=x+4 <em>Distribute</em>
2x=16<em> Subtract x from both sides and add 12 to both sides</em>
x=8 <em>Divide each side by 2.</em>
<em> </em>
<em />
Answer with Step-by-step explanation:
We are given that
u+ v and u-v are orthogonal
We have to prove that u and v must have the same length.
When two vector a and b are orthogonal then

By using the property

We know that



Magnitude is always positive
When power of base on both sides are equal then base will be equal
Therefore,

Hence, the length of vectors u and v must have the same length.
Answer:
See below.
Step-by-step explanation:
First, notice that this is a composition of functions. For instance, let's let
and
. Then, the given equation is essentially
. Thus, we can use the chain rule.
Recall the chain rule:
. So, let's find the derivative of each function:

We can use the Power Rule here:
Now:

Again, use the Power Rule and Sum Rule

Now, we can put them together:


2/3 of a box per 30 secs
2/3 times 2 = 4/3 = 1 1/3