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inessss [21]
2 years ago
10

What is the square root of 25? Then add that to 17 and what is your answer? I have no idea. Hint, it's a Taylor Swift song.....

tell me some of the lyrics. Merry Christmas!
Mathematics
2 answers:
IgorLugansk [536]2 years ago
8 0

Answer:

Once upon a time, a few mistakes ago.

I was in your sights, you got me alone.

You found me (3x)

I guess you didn't care, and I guess I liked that.

And when I feel hard, you took a step back.

Without me (3x)

Pre-chorus:

And he is longe gone

When he is next to me

And I realize the balme is on me

Chorus:

'Cause I knew you were trouble when you walked in

So shame on me now

Flew me to places I had never been

So you put me down oh

I knew you were trouble when you walked in

So shame on me now

Flew me to palces I had never been

Now I'm lying on the cold hard ground

Oh, oh, trouble, trouble, trouble

Oh, oh, trouble, trouble, trouble

No apologies, he'll never see you cry

Pretend he doesn't know, that he's the reason why

You're drowning (3x)

And I hear you moved on, from whispers on the street

A new notch in your belt, is all I'll ever be

And now I see, now I see, now I see

Pre-chorus:

He was long gone

When he met me

And I realize the joke is on me

Chorus:

'Cause I knew you were trouble when you walked in

So shame on me now

Flew me to places I had never been

So you put me down oh

I knew you were trouble when you walked in

So shame on me now

Flew me to palces I had never been

Now I'm lying on the cold hard ground

Oh, oh, trouble, trouble, trouble

Oh, oh, trouble, trouble, trouble

When your saddest fear comes creeping in

That you never loved me or her or anyone or anything

Yeah

Chorus:

'Cause I knew you were trouble when you walked in

So shame on me now

Flew me to places I had never been

So you put me down oh

I knew you were trouble when you walked in

So shame on me now

Flew me to palces I had never been

Now I'm lying on the cold hard ground

Oh, oh, trouble, trouble, trouble

Oh, oh, trouble, trouble, trouble

I knew you were trouble when you walked in

Trouble, trouble, trouble

I knew you were trouble when you walked in

Trouble, trouble, trouble

Step-by-step explanation:

77julia77 [94]2 years ago
6 0

Answer:

this made me so happy :)

Step-by-step explanation:

it seems like one of those nights this place is too crowded, too many cool kids. it seems like one of those night we ditch the whole scene, and end up dreamin, instead of sleeping.

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Divide 794.1 by 7.61. Round off your answer to two decimal places. A. 104.35 B. 786.49 C. 95.83 D. 1,043.50
VikaD [51]
Answer: 
A. 104.35

Explanation: 
794.1 ÷ 7.61 = 104.34954 
Round off to two decimal places: 
104.349 
round 4 up to 5 because the next number is greater than 5: 
9 > 5 
So 
104.35
3 0
3 years ago
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Which statement explains the relationship between corresponding terms in the table?
Anna11 [10]
Maybe another day in the life of who knows what im talking about
7 0
3 years ago
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Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE
AVprozaik [17]

Answer:

D

Step-by-step explanation:

We are given that:

\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}

Using double angle identities:

\displaystyle  \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2>\displaystyle  \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}</h2>

Simplify:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}

Evaluate:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}

So, our answer is D.

7 0
3 years ago
The side of a square is 3^2 inches. Using the area formula A = s^2, determine the area of thesquare.
elena55 [62]

Answer: it’s 81

Step-by-step explanation:

easy math I know it’s 81

3 0
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Hayden lives in Jefferson City, MO, which has a population of 48, 838. He says Kansas City's population is about
ladessa [460]

Answer:

the awser is d if you round it up

Step-by-step explanation:

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