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3 years ago

A double replacement reaction can be best described as a reaction in which

2 answers:

8 0

You have two nonmetal formulas and they switch. I think that's it. It'll get you partial credit at least. I hope it helps!

klasskru [66]3 years ago

7 0

Answer:

Explanation:

A double repalcement reaction is a type of reaction in which there is exchange of ions between two compounds leading to the formation of new products. It is also known as double displacement reaction.

BC+DE produces BE+CD.

A double replacement reaction leads to the formation of two new compounds Be and CD.

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Mechanical waves need mediums. or else it isn't a mechanical wave

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3 years ago

What alkyl halide forms the following alkene as the only product in an elimination reaction?

lorasvet [3.4K]

Answer:

C(CH3)3 I - iodide

Explanation:

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3 years ago

Why can't amylase digest other substances?

yuradex [85]

Explanation:

saliva contains and amylase which randomly hydrogen all the one is equal to 4 glycosidic bonds of stars except it's out most bones and those next the branches on the hand glycogen being a highly branched molecule it is evident that amylase won't be a good animal eyes to digest it due to physical structure constance

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2 years ago

Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

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3 years ago

Give the major product formed when phenol is heated with concentrated H2SO4 and SO3. (There is more than one correct answer, but

iris [78.8K]

Answer:

See image attached and explanation

Explanation:

The reaction of phenol with SO3/H2SO4 is an electrophilic reaction. The electrophile attacks portions of high electron density in the substrate phenol.

The -OH group activates phenol towards electrophilic substitution at the ortho and para positions, hence the product(s) formed in this reaction(only one product is shown here as required by the question).

The sulphonation of phenol using concentrated sulfuric acid at lower temperature yields majorly the ortho product whereas at higher temperature the para product predominates.

4 0

3 years ago