Question

"what is the pressure of a 34.8-l gas sample containing 7.45 mol of gas at 19.9°c? (r = 0.0821 l • atm/(k • mol), 1 atm = 760 torr)"

Answer 1

Answer:

The gas pressure is 5.15 atm

Explanation:

Given:

Volume of gas, V = 34.8 L

Moles of gas, n = 7.45 moles

Temperature, T = 19.9 C

To determine:

Pressure, P of the gas

Explanation:

Based on the ideal gas equation:

$PV = nRT$

where P = pressure, V = volume, n = moles, T = temperature, R = gas constant

$P = \frac{nRT}{V} \\\\P = \frac{7.45\ moles*0.0821\ Latm/mol-K*(19.9+273)\ K}{34.8\ L} =5.15\ atm$

Answer 2

You can solve this problem using ideal gas formula (PV=nRT). Remember that the temperature used is Kelvin, so 19.9°c would be: 19.9+ 273.15= 293.05°K

PV=nRT
P= nRT / V
P= 7.45 * 0.0821* 293.05 / 34.8
P= 5.15 atm = 3914.5 torr