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kramer
3 years ago
15

Jennifer has 84.5 yards of fabric to make curtains she makes 6 identical curtains and has 19.7 yards of fabric remaining how man

y yards of fabric does Jennifer use per curtain ?show your work or explain your answer​
Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Answer: She uses 10.8 yards of fabric per curtain.

Step-by-step explanation:

84.5 - 19.7 = 64.8

64.8/6 = 10.8

garri49 [273]3 years ago
4 0

Answer:

10.8 yards per curtain

Step-by-step explanation:

Jennifer starts with 84.5 yards and has 19.7 yards remaining when she's finished; this means she used

84.5-19.7 = 64.8 yards.

She made 6 curtains with these; this means she used

64.8/6 = 10.8 yards per curtain.

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A parallelogram is formed by the supports that attach a basketball backboard and rim to the wall. The angles change as the baske
irina [24]

The measure of angle BCD is 32 degrees

<h3>How to determine the value of BCD?</h3>

The image of the parallelogram that completes the question is added as an attachment.

The given parameter is:

m<DAB = 32 degrees

From the attached image, we can see that BCD and DAB are opposite angles.

Opposite angles of a parallelogram are equal.

So, we have:

BCD = 32 degrees

Hence, the measure of BCD is 32 degrees

Read more about parallelograms at:

brainly.com/question/21322889

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3 0
1 year ago
A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
3 years ago
0.1562 rounded to the nearest hundredth place
kondaur [170]

Answer:

0.16

Step-by-step explanation:

if the number in the thousandths is 5 or over you round it up.

3 0
3 years ago
Read 2 more answers
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seraphim [82]

Answer:

66 is 49.2537313% of 134

Step-by-step explanation:

so 49.26

7 0
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Shtirlitz [24]

Answer:

14%

Step-by-step explanation:

To get the percent increase divide 0.8 by 0.7

0.8/0.7 ≈ 1.14285714286

So the percent increase would by about 14 percent

3 0
2 years ago
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