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Snezhnost [94]
3 years ago
8

Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.

Mathematics
1 answer:
Digiron [165]3 years ago
6 0

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

x ^ 2-1 = 0\\x ^ 2 = 1

So the roots are:

x = 1\\x = -1

Therefore we can write the expression in the following way:

x ^ 2-1 = (x-1)(x + 1)

Now the expression is as follows:

\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

x = 1\\x = -1\\x = 2

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

(x-1)\geq0 when x\geq-1

(x + 1)\geq0 when x\geq1

and

(x-2) ^ 2 is always \geq0

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

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Select the graph and the description of the end behavior of f(x) = x3 + 2.
Dmitry [639]
F(x)=x^3+2
we see the power is odd
the ends go in opsoite directions
we know that if the leadind coefient (number in front of highest power term) is positive, then odd powered polynomials go from bottom left to top right
and for even ones, it goes both up

for negative, odd ones go from top left to bottom right
for even, both go down

we gots
f(x)=1x^3+2
positive and odd, so it goes from bottom left to top right

as x approaches negative inifnity, y approaches negaitve infinity
as x approaches infinity, y approaches infinity
8 0
3 years ago
Read 2 more answers
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vazorg [7]

Answer:

? can you explain this a little better

Step-by-step explanation:

3 0
3 years ago
N
ZanzabumX [31]

Answer:

x = 4 is the solution

Step-by-step explanation:

given  = x ( square both sides )

x + 12 = x² ( rearrange into standard form )

x² - x - 12 = 0 ← in standard form

(x - 4 )(x + 3 ) = 0 ← in factored form

equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 3 = 0 ⇒ x = - 3

Insert these values into the original equation, and if both sides are equal, and those are the solutions.

x = 4 :  =  = 4 = x ← correct

x = - 3 :  =  = 3 ≠ - 3 ← false

the answer is x = 4

7 0
3 years ago
Please help me thank you!
sergiy2304 [10]

Answer:

The equation of the line that passes through the points

(5,2) and (-5,6)

is

y=-2/5x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,2) and (-5,6).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=2.

Also, let's call the second point you gave, (-5,6), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=6.

Now, just plug the numbers into the formula for m above, like this:

m= 6 - 2/-5 - 5 or m= 4-10 or m=-2/5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-2/5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,2). When x of the line is 5, y of the line must be 2.

(-5,6). When x of the line is -5, y of the line must be 6.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-2/5x+b. b is what we want, the -2/5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,2) and (-5,6).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,2). y=mx+b or 2=-2/5 × 5+b, or solving for b: b=2-(-2/5)(5). b=4.

(-5,6). y=mx+b or 6=-2/5 × -5+b, or solving for b: b=6-(-2/5)(-5). b=4.

3 0
3 years ago
What are the zeros of the polynomial function f(x) = x3 + 10x2 + 24x?
Amiraneli [1.4K]
X^3 + 10x^2 + 24x

divide by x
x(x^2 + 10x + 24)

factor it
x(x+4)(x + 6)

now solve for x

the answer is -6,0,-4
8 0
3 years ago
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