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AlladinOne [14]
3 years ago
10

What is the graph of the inequality? 4x + 2y ≤ 6

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0
The graph is Y= 2x + 3
frozen [14]3 years ago
6 0

Answer:

Graph Attached.

Step-by-step explanation:

Given: 4x+2y\leq 6

We need to draw the graph of linear inequality.

First we write inequality as equality and then make table of x and y

New equation: 4x+2y=6

  x       y  

 0       3

 1        1

 2      -1

Now, we take test point (0,0) to verify the shaded region.

4(0)+2(y)\leq 6

0\leq 6

TRUE

Now we plot the points on graph and then draw graph.

Please see the attachment for graph.

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The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form
azamat

Answer:

\large \boxed{y = (x - 5)^{2} + 2 }

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}The figure below shows that your parabola has its vertex at (5,2).

4 0
3 years ago
Pls help don’t answer if you don’t know ill give out brainliest
Vesnalui [34]

I want to help but i cant see the picture! tell me the question and i will solve it!

5 0
3 years ago
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