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2 years ago

Find the first, fourth, and eighth terms of the sequence. A(n) = −2 ∙ 2x − 1

1 answer:

Nutka1998 [239]2 years ago

5 0

$A(n)=-2\cdot2^{n-1}\\\\\text{Find the first, fourth, and eighth terms}\\\text{It means}\ A(1),\ A(4)\ \text{and}\ A(8).\\\\\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{in}\ A(n):\\\\A(1)=-2\cdot2^{1-1}=-2\cdot2^0=-2\cdot1=-2\\\\A(4)=-2\cdot2^{4-1}=-2\cdot2^3=-2\cdot8=-16\\\\A(8)=-2\cdot2^{8-1}=-2\cdot2^7=-2\cdot128=-256\\\\\boxed{Answer:\ -2,\ -16,\ -256}$

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For the past several years, the high school theater department has performed a musical in their auditorium. Each year since the

goblinko [34]

Answer:

D. The independent variable is the number of ticket price increases, and the dependent variable is the ticket sales.

Step-by-step explanation:

The wording, "the table shows A <em>with respect to</em> B" means that "B" is the independent variable. Here, "B" is "the number of times they have increased the price of the ticket." That is ...

the independent variable is the number of ticket price increases

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2 years ago

Mandy has 8 ounces of fish food to feed her fish . she feeds the fish 0.4 of fish food at each feeding how many times can Mandy

sergejj [24]

20 times

This is just simple division. Do 8 divided by 0.4 and you should get 20

Hope this helps!
-Coconut;)

8 0

2 years ago

I only need help with the second part of this question. please can you help?

matrenka [14]

13,822 to one significant figure is 10,000

623 to one significant figure is 600

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6,000,000/10 = 600,000

4 0

2 years ago

Which number would fit in?

almond37 [142]

Answer:

Answer is 3/6th

Step-by-step explanation:

Because 2/4 is a half so what is 3 as a half of a fraction which is

3/6

5 0

2 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago