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nalin [4]
3 years ago
5

Adding/subtracting polynomials ​

Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

g(x) - h(x) =  { - x}^{4}  - 11x

Step-by-step explanation:

g(x) =  {6x}^{2}  - 4x +  {3x}^{4}

h(x) =  {6x}^{2}  + 4 {x}^{4}  + 7x

g(x) - h(x)

({6x}^{2}  - 4x +  {3x}^{4})  - ( {6x}^{2}  + 4 {x}^{4}  + 7x)

{6x}^{2}  - 4x +  {3x}^{4}   - {6x}^{2}   -  4 {x}^{4}   -  7x

( {3x}^{4}  -  {4x}^{4}) +  ( {6x}^{2}  - 6x {}^{2} ) + ( - 4x - 7x)

{ - x}^{4}  - 11x

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Answer:

root 6

Step-by-step explanation:

pi*r^2 = A

6*pi*r^2 = 6A

6*r^2 = new radius squared

root 6 * r = new radius

3 0
3 years ago
Pls help work due in 10 min What is 0.000005 in scientific notation
Rus_ich [418]

Answer:

5 × 10 ^ -6

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which can also be written as 5 × 10 ^ -6

hope it helps

8 0
4 years ago
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Help me solve this algebra question pleaseeeeee 3(6-4x)-27x+10x-31
Sonja [21]
3(6-4x)-27x+10x-31    =

18-12x-27x+10x-31     distributed. =

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5 0
3 years ago
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A line passes through (10,4) and (13,-11). Write the equation of the line in standard form.
AlexFokin [52]

\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{13}~,~\stackrel{y_2}{-11}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-11-4}{13-10}\implies \cfrac{-15}{3}\implies -5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-5(x-10)


now

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

therefore,


\bf y-4=-5(x-10)\implies y-4=-5x+50\implies \blacktriangleright 5x+y=54 \blacktriangleleft

7 0
4 years ago
(lg 5)²+(lg 2)(lg 50)<br>need solution....​
-Dominant- [34]
-125g ^2 that’s what I got solving for it
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3 years ago
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