Answer:
2cosAcos2A, 4sinAcos^2A
Step-by-step explanation:
cos3A+cosA
2cos((3A+A)/2)cos((3A-A)/2)
2cos(4A/2)cos(2A/2)
2cosAcos2A
sin3A+sinA
2sin((3A+A)/2)cos((3A-A)/2)
2sin(4A/2)cos(2A/2)
2sin2AcosA
4sinAcos^2A
A,C,B
This is the answer;BC,AB,CA
-3/2
Down 3
Right 2
As an improper fraction it would be -1 1/2
Answer:
I think it is 24 but I don't know the rest sorry 乁( •_• )ㄏ
Answer:
The solution is the point (18,0)
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system by substitution
substitute equation B in equation A

solve for x
Adds (1/3)x both sides


Adds 6 both sides



<em>Find the value of y</em>
substitute the value of x in equation A or equation B

therefore
The solution is the point (18,0)