3 years ago

Twice the difference of a number and 4 is equal to the sum of the number and 3

Mathematics

2 answers:

pickupchik [31]3 years ago

5 0

The number, x, is 11

Leya [2.2K]3 years ago

3 0

The answer is 11...
2 x 4 = 8, then you do 8 + 3 which is 11, hope this helped :)

You might be interested in

Solve the equation <br> 2x+1=-1

Olenka [21]

Answer:

2x=-1-1

2x=2

x=2×2

x=4

4 0

3 years ago

Read 2 more answers

If 28% of a sum is 100.80 what is the sum

Sveta_85 [38]

$360.00*.28= 100.80

<span>Or do a portion </span>

<span>28%/100%=100.8/x </span>

<span>Then cross multiply </span>

<span>10080=28x </span>

<span>x=360</span>

4 0

3 years ago

Find the inner product for (3,1,4)*(2,8,2) and state whether the vectors are perpendicular.

faltersainse [42]

Good evening ,

Answer:

<h2>•• Inner product = 3×2 + 1×8 + 4×2 = 22</h2><h2 /><h2>•• since 22 ≠ 0 then the vectors are not perpendicular.</h2>

5 0

3 years ago

Read 2 more answers

What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4

Alecsey [184]

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: $f(x)=\dfrac{3x^2}{x^2-4}$

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. $x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2$

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at $y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}$

i.e. $y=\dfrac{3}{1}=3$

Hence, f(x) will have horizontal asymptote at y=3.

3 0

3 years ago

What is 20 divided by 10 but to the power or 2

Klio2033 [76]

4 is the answer for your question

5 0

2 years ago

Read 2 more answers