All categories

3 years ago

What is the coefficient in this problem -4x+36=

1 answer:

8 0

A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 3 in 3x).

So the coefficient is 4 because it is multiplied with a variable.

hope it helps!

You might be interested in

I need help please, I will give whoever answers this gets brainliest

dusya [7]

Hey!!

H (2,1),(4,3),(6,5),(2,7) is not a function.

please see the attached picture

Hope it helps

Good luck on your assignment

4 0

3 years ago

All of the teachers at Chapel Glen are working together to make a HUGE snow fort! They need a total of 118 snow bricks, each wei

pogonyaev

Step-by-step explanation:

interested girls only

id : 495 842 5906

pass: TkD16c

5 0

3 years ago

Find the perimeter of ABC with vertices A (1,1), B (7,1), and C (1,9)

Effectus [21]

Answer:

24 unit

Step-by-step explanation:

Given,

The vertices of the triangle ABC are,

A (1,1), B (7,1), and C (1,9),

By the distance formula,

$AB=\sqrt{(7-1)^2+(1-1)^2}=\sqrt{6^2}=6\text{ unit}$

$BC=\sqrt{(1-7)^2+(9-1)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10\text{ unit}$

$CA=\sqrt{(1-1)^2+(1-9)^2}=\sqrt{8^2}=8\text{ unit}$

Thus, the perimeter of the triangle ABC = AB + BC + CA = 6 + 10 + 8 = 24 unit

4 0

3 years ago

How does the area change?

kap26 [50]

Garden a is doubled to get garden b

6 0

3 years ago

All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage

tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

$\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}$

Now, we can calculate the standard deviation as:

$\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}$ $\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}$

Answer: the standard deviation of this population is approximately 10.33

3 0

2 years ago