Answer:cost of each pound of apple= $3
And cost of each pound of orange =$2
Step-by-step explanation:
Step 1
Let cost of apples = x
And cost of Oranges =y
Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as
6 x + 3y= 24----- equation 1
Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as
5x+ 4y= 23----- equation 2
Step 2
6 x + 3y= 24----- equation 1
5x+ 4y= 23----- equation 2
Using substitution method to solve the equation
6 x + 3y= 24
24-6x=3y
y= 24-6x/3 = 8-2x
Y= 8-2x
Substituting the value of y= 8-2x into equation 2
5x+ 4( 8-2x)= 23
5x+ 32 -8x= 23
32-23= 8x-5x
9=3x
x=9/3
x=3
Putting the value of x= 3 in equation 1 and solving to find y
6 x + 3y= 24
6(3) +3y= 24
18+3y=24
3y= 24-18
3y=6
y=6/3= 2
Therefore the cost of each pound of apple= $3
And cost of each pound of orange =$2
H(-6) = 2(-6) + 5
h(-6) = -12 + 5
Solution: h(-6) = -7
Answer:
ok
Step-by-step explanation:
Answer:
Whole Number : 6
Integers: -6 and 6
Rational Number: -6.0 and -6/1
Irrational Number: -Infinity or -0
Answer:
The answer is 1/9.
Step-by-step explanation:
Using the equation a-b=2, we can solve that a = 2+b.
We can then <u>substitute that into the expression</u> given to get 3^b/3^(2+b).
Since <u>they have the same base, we can subtract the exponents from the numerator and denominator</u> to get 3^(b-2-b) which <em>simplifies to 3^-2.</em>
3^-2 is simply 1/9.
