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Oxana [17]
3 years ago
5

What is that solution to this inequality 2(x-4)+14<=x-1

Mathematics
2 answers:
Fed [463]3 years ago
6 0
2(x-4)+14\leq x-1\\&#10;2x-8+14\leq x-1\\&#10;2x-x\leq-1+8-14\\&#10;x\leq-7
Varvara68 [4.7K]3 years ago
3 0
2(x-4)+14\leq x-1\\2x+2(-4)+14\leq x-1\\2x-8+14\leq x-1\\2x+6\leq x-1\ \ \ \ |subtract\ 6\ from\ both\ sides\\2x\leq x-7\ \ \ \ |subtract\ x\ from\ both\ sides\\\boxed{x\leq-7\to x\in(-\infty;-7]}
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Sliva [168]

Answer:  A) 126.6

<u>Step-by-step explanation:</u>

Since we know ∠B = 85° and ∠C = 53°, we can use the Triangle Sum Theorem (angles of a triangle = 180°) to calculate ∠A.

∠A + ∠B + ∠C = 180

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                       A = 42          B = 85       C = 53

                       a = 85          b = ???       c = ???

We have all of the information for ∠A and side a so we can use the Law of Sines to find b (AC).

\dfrac{\sin 42}{85}=\dfrac{\sin 85}{b}\\\\\\b(\sin 42)=85(\sin 85)\\\\\\b=\dfrac{85\sin 85}{\sin 42}\\\\\\b=\large\boxed{126.547}

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