<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
6.241 I think that's right
Answer:
AOE = 138, EOD = 48
Step-by-step explanation:
Since AD is the diameter of the circle and goes through the middle
angle AOE + angle EOD = 180
Solving the equation (x + 138) + ( x+ 48) = 180
We get x = 0.
Answer:
I am pretty sure that it's C
Step-by-step explanation:
you need to do a^2+b^2=c^2
Answer:
440
Step-by-step explanation
Idk exactly how to do it but hopfuly its right because it came from somone else give credit to him/her
