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olga_2 [115]
3 years ago
12

The sum of two numbers is 44, and the larger number is 2 more than the smaller number. What is the smaller number? If x = the sm

aller number and y = the larger number, then which of the following systems of equations represents the word problem?
A. x + y = 44 and y = x + 2
B.x + y = 44 and y = 2x
C.x + y = 44 and x = y + 2
Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0

x + y = 44 and y = x + 2 represents the word problem

hope I helped

Nastasia [14]3 years ago
6 0
A because y is larger than x by 2.

x + y = 44
y = x + 2

Substitute eqn 2 into eqn 1
x + x + 2 = 44
2x = 42
x = 21

Thus, the smaller number is 21.
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The length of a rectangle is 3 more yrd than twice the width. The area is 869yrd^2
Otrada [13]

Width=20.108 yrd and Length=43.216 yrd

Step-by-step explanation:

Let width = w

Length =3+2w

Area = 869 yrd^2

We need to find length and width of rectangle.

The formula used is:

Area= length*width

Putting values:

Area= length*width

869= (3+2w)*(w)

869= 3w+2w^2

2w^2+3w-869=0

Using quadratic equation to find value of width w:

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a=2, b=3 and c=-869

w=\frac{-3\pm\sqrt{(3)^2-4(2)(-869)}}{2(2)}

w=\frac{-3\pm\sqrt{6961}}{4}

w=\frac{-3\pm 83.4}{4}

w=\frac{-3+83.4}{4}\,\,and\,\,w=\frac{-3-83.4}{4}

w=20.108\,\,and\,\,w=-21.6

Since width can't be negative so, width w=20.108

Length will be: L=3+2w = 3+2(20.108)=3+40.216=43.216

So, Width=20.108 yrd and Length=43.216 yrd

Keywords: Area of rectangle

Learn more about Area of rectangle at:

  • brainly.com/question/3306327
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  • brainly.com/question/6564657

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