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2 years ago

Use Gauss's approach to find the following sums (do not use formulas). a. 1+2+3+4+...+98

Mathematics

1 answer:

Blababa [14]2 years ago

6 0

Here ya go im 90% sure this is the right answer enjoy!

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Evaluate the expression . 3/4•1/2+1

Travka [436]

3/1 x +1 that the answer

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2 years ago

How to solve and simplify to the smallest fraction

Ostrovityanka [42]

Answer:

7/12

Step-by-step explanation:

When you multiply fractions you just multiply across. 7*6 = 42 and 8*9 = 72. The both of these numbers can be divided by six so 42/6 = 7 as the numerator. 72/6 = 12 for the denominator. 7/12 is the answer.

3 0

2 years ago

Which expression is equivalent to 10p - 35?

s344n2d4d5 [400]

Answer:

a: $5\left(2p-7\right)$

Step-by-step explanation:

$10p-35$

$5* \:2p-5* \:7$

$5\left(2p-7\right)$

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2 years ago

Read 2 more answers

Evaluate the expression (- n) ^ (n + n) + n ^ (n - n) , when n = 2

sladkih [1.3K]

Answer:

Step-by-step explanation:

Substitute the value of the variable and simplify.

$(-(2))^{(2+2)} +2^{(2-2)}$

$-2x^{2+2} =2^{4} = 16$

$2^{2-2} =2^{0}$

Anything raised to the power of 0 is one.

16 + 1 = 17

5 0

3 years ago

Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin

34kurt

Answer:

$\dfrac{1}{30}$

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

$\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}$

7 0

3 years ago

Use​ Gauss's approach to find the following sums​ (do not use​ formulas). a. 1+2+3+4+...+98

Use Gauss's approach to find the following sums (do not use formulas). a. 1+2+3+4+...+98