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NikAS [45]
3 years ago
6

Hellpppppppp Mmeeeeeeeeeeeee

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

17

Step-by-step explanation:

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Plss help for a brainlist
Marizza181 [45]

Answer:

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3 0
3 years ago
A firm maintains 22 cars for business purposes. From past experience, it is known that approximately 10% will require major engi
seropon [69]

Answer:

The probability that at most 1 car will require major engine repair next year is P=0.3392.

Step-by-step explanation:

This can be modeled as a binomial random variable, with n=22 and p=0.1.

The probability that exavtly k cars will require major engine repair next year is:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}

Then, the probability that at most 1 car will require major engine repair next year is:

P(x\leq1)=P(x=0)+P(x=1)\\\\\\P(x=0) = \dbinom{22}{0} p^{0}(1-p)^{22}=1*1*0.0985=0.0985\\\\\\P(x=1) = \dbinom{22}{1} p^{1}(1-p)^{21}=22*0.1*0.1094=0.2407\\\\\\P(x\leq1)=0.0985+0.2407\\\\P(x\leq1)=0.3392

3 0
3 years ago
What value of y makes the equation true? -7/12=y/-36
STALIN [3.7K]
-7/12=y/-36
times both sides by -36 (-36=12*-3)
-3*-7=y
21=y

y=-21
7 0
3 years ago
Solve the system of linear equations by graphing.
Inga [223]

Answer:

The solution is shown in the graph.

x= 2.3

y= 4.3

3 0
3 years ago
Please someone explain this one? Thank you!
den301095 [7]
About 7,460 punds if you add everything together

5 0
3 years ago
Read 2 more answers
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