Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says " times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
2. Charlene's rhombus:
Dividing the area calculated, you get:
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
∠ EML = 94°
Step-by-step explanation:
See the attached diagram.
The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.
Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°
Hence, (x + 97) + ( x + 66) + 141 = 360
⇒ 2x + 304 = 360
⇒ 2x = 56
⇒ x = 28
So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)
Step-by-step explanation:
use CAH method (Cos angle = adjacent/hypotenuse)
Given adjacent = 5
Hypotenuse = 12,