Answer:
- modulus: 3√2
- argument: -3π/4 (or 5π/4)
Step-by-step explanation:
The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).
__
<h3>rectangular form</h3>
The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:

<h3>polar form</h3>
The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:
modulus = √((-3)² +(-3)²) = 3√2
The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.
arg = arctan(-3/-3) = -3π/4 or 5π/4 . . . . radians
__
modulus∠argument = (3√2)∠(-3π/4)
B is true because the second graph has a lower average
The slope formula can be used to prove a triangle has a right angle
Answer:
sorry kid idontknow
Step-by-step explanation:
Answer:
Step-by-step explanation:
Discussion
The object of this is make w by itself on one side of the equation.
Equation
x = 3 (y + w) - 1 Add 1 to both sides of the equation.
x + 1 = 3(y + w) - 1 + 1 Combine
x + 1 = 3(y + w) Remove the Brackets
x + 1 = 3y + 3w Notice y and w are affected by the 3. Subtract 3y
x + 1 - 3y = 3y-3y + 3w Combine
x + 1 = 3w Divide both sides by 3
(x +1)/3 = 3w/3
(x + 1)/3 = w
Answer: (x + 1)/3 = w