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amm1812
3 years ago
9

Mercel earns $13.40/h works 40 hours a week.

Mathematics
1 answer:
garri49 [273]3 years ago
4 0
You multiple 40h with $13.40 then with 52 and then finally divide by 12 so the answer is $2,322
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a 1 kg ball has 10 joules of kinetic energy and starts to roll up a hill how far up the hill will it be when it stops
AURORKA [14]

Answer:

<em>The ball will roll upto </em><em>1 m.</em>

Step-by-step explanation:

A 1 kg ball has 10 joules of kinetic energy and starts to roll up a hill.

As along the hill the ball rises up, it loses its kinetic energy. The kinetic energy is converted to potential energy.

According to the law of conservation of energy, the kinetic energy plus the potential energy equals a constant.

Here given kinetic energy as 10 J, so this energy will get converted to potential energy.

We know that, potential energy is

P.E=m\cdot g\cdot h

where,

m is the mass, g is the acceleration due to gravity and h is the height.

Putting the values,

\Rightarrow 10=1\times 10\times h

\Rightarrow 10=10 h

\Rightarrow h=1\ m

7 0
3 years ago
Can someone help me with this problem.
Oksanka [162]

Answer:

negative because the container is losing liquid.

Step-by-step explanation:

y-5x is the rate

7 0
3 years ago
Could I get some help? QUESTION: This table shows the profit for a company (in millions of dollars) in different years.
Pani-rosa [81]

Answer:

17 million

Step-by-step explanation:

-0.34(8^{2}) + 4.43(8) + 3.46

-21.76 + 35.44 + 3.46

13.68 + 3.46

17.14

Answer: C 17 million

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7 0
2 years ago
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
X^2+5x=3x+11 solve by completing the square
goldenfox [79]
X^2+2x-11=0, this would be the answer that you are looking for m8.
7 0
3 years ago
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