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2 years ago

A towns population increased from 14523 to 16489 what is the percent increase in the towns population

2 answers:

8 0

First you need to figure out how much it increased by. 16489-14523= 1966
The population increased by 1966. Now you just need the percentage. You should get the percentage by dividing the increase in population by the original population. That would be 1966/14523=0.135. To get the percentage you must multiply 0.135 by 100.
0.135 x 100= 13.5%
That should be the answer.

MrRissso [65]2 years ago

5 0

Answer:14%

Step-by-step explanation:

Your welcome

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Triangle JKL has vertices J(-4, -1), K(0, 4), and L(-4, -2). Graph The triangle and it’s image after a dilation with a scale fac

Dafna1 [17]

Answer:

J(-2, -0.5), K(0, 2), L(-2, -1)

Step-by-step explanation:

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2 years ago

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adoni [48]

Answer:

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3 years ago

IXL!! I WILL ADD BRAINLIST!

klio [65]

Answer:

-3,3.1, 3 2/10

Step-by-step explanation:

When you are putting different numbers from least to greatest, you need to put them in the same form...

First things first we should put -3 wayy up front. negative numbers are worth less than positive numbers.

Then we need to turn 3 2/10 into a decimal.

3 2/10 -------> 3.2

3.2 is more than 3.1

Thus, the order is

-3,3.1, 3 2/10

Hope this helps and have a nice day.

8 0

2 years ago

Read 2 more answers

You earned 90% on a science quiz. You answered 27 questions correctly. How many questions were on the test?

Scilla [17]

Answer:

There were 30 questions on the test.

Step-by-step explanation:

1. Set up your equation: 27/90 = y/100

2. Next you want to cross multiply: 2700 = 90y or 270 = 9y

3. Divide 270 by 9 to find your y: y = 30

There were 30 questions on the test.

7 0

3 years ago

What are the factors of 3x²+7x-20?

Leya [2.2K]

$3x^2+7x-20=0\\\\a=3;\ b=7;\ c=-20\\\\\Delta=b^2-4ac\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=7^2-4\cdot3\cdot(-20)=49+240=289;\ \sqrt\Delta=\sqrt{289}=17\\\\x_1=\frac{-7-17}{2\cdot3}=\frac{-24}{6}=-4;\ x_2=\frac{-7+17}{2\cdot3}=\frac{10}{6}=\frac{5}{3}\\\\\\3x^2+7x-20=3(x+4)(x-\frac{5}{3})\\\\\\3x^2+7x-20=0\iff x=-4\ \vee\ x=\frac{5}{3}$

4 0

3 years ago