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zhannawk [14.2K]
3 years ago
10

Find the measure of the exterior angle 1. with one angle is 50 degrees and 28 degrees​

Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer:

D. 78°

Step-by-step explanation:

50°+28°= 78°

_______

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A scale drawing of a rectangular park is 5 inches wide and 7 inches long. The actual park is 280 yards long. What is the area of
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56,000

Step-by-step explanation:

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3 years ago
Solve 8x 2 - 2x - 1 = 0<br><br> {-1/4, 1/2}<br> {-1/2, 1/4}<br> {1/2}
Kamila [148]
<span>8x^2 - 2x - 1 = 0
(2x - 1)(4x + 1) = 0
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answer
</span><span>{-1/4, 1/2}</span>
4 0
4 years ago
Boatesville is 65 3/5 kilometers from Stanton. A bus traveling from Stanton is 24 1/3 kilometers from Boatesville. Write an equa
Elena L [17]
Distance the bus has traveled :

65 \dfrac{3}{5}  -  24\dfrac{1}{3}

= 65 \dfrac{3 \times 3 }{5 \times 3}  -  24\dfrac{1 \times 5}{3 \times 5}

= 65 \dfrac{9 }{15}  -  24\dfrac{5}{15}

= 41 \dfrac{4 }{15}  \text { km}

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\text {Answer : The bus has traveled }41 \frac{4}{5} \text { km}
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8 0
3 years ago
Consider the growth of a population p(t). It starts out with p(0)=A. Suppose the growth is unchecked, and hence p′=kp for some c
gayaneshka [121]

Answer:

p(t) = Ae^{\frac{kt^2}{2}}

Step-by-step explanation:

We are given the following information in the question:

The growth of population is given by the function p(t).

p(0)=A where A is a constant.

p' = kp

where k is a constant.

Solving the given differential equation, we have,

p' = kp\\\\\displaystyle\frac{dp}{dt} = kp\\\\\frac{dp}{p} = kt~ dt\\\\\text{Integrating both sides}\\\\\int \frac{dp}{p} = \int kt~ dt\\\\\log p = \frac{kt^2}{2} + C\\\\\text{where C is the integration constant}\\\\\text{Putting t = 0}\\\\\log p_0 = C\\\\\log p = \frac{kt^2}{2} + \log p_0\\\\\log p - \log A = \frac{kt^2}{2}\\\\\log \frac{p}{A} = \frac{kt^2}{2}\\\\p(t) = Ae^{\frac{kt^2}{2}}

5 0
3 years ago
An unfair coin has probability 0.3 of landing heads. The coin is tossed seven times. What is the probability that it lands heads
solmaris [256]

Answer:

0.9176 = 91.76% probability that it lands heads at least once

Step-by-step explanation:

For each time that the coin is tossed, there are only two possible outcomes. Either it lands heads, or it does not. The probability of a toss landing heads is independent of other tosses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An unfair coin has probability 0.3 of landing heads.

This means that p = 0.3

The coin is tossed seven times.

This means that n = 7

What is the probability that it lands heads at least once?

Either it does not lands heads, or it lands at least once. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.3)^{0}.(0.7)^{7} = 0.0824

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0824 = 0.9176

0.9176 = 91.76% probability that it lands heads at least once

5 0
4 years ago
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