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madreJ [45]
4 years ago
14

How many atoms are in 0.750 moles of zinc?

Chemistry
1 answer:
Ira Lisetskai [31]4 years ago
4 0
1 mole Zn ---------- 6.02 x 10²³ atoms
0.750 moles Zn ----- ? 

atoms = 0.750 * ( 6.02 x 10²³ / 1 )

= 4.515 x 10²³ atoms

hope this helps!


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Hence the mechanical advantage of the screwdriver is 0.40.
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By stoichiometry and assume that:

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How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

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MaVa/MbVb = nA/nB

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Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

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3 years ago
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