We have to get the relationship between metallic character and atomic radius.
Metallic character increases with increase in atomic radius and decrease with decrease of atomic radius.
If electrons from outermost shell of an element can be removed easily, that atom can be considered to have more metallic character.
With increase in atomic radius, nuclear force of attraction towards outermost shell electron decreases which facilitates the release of electron.
With decrease in atomic radius, nuclear force of attraction towards outermost shell electrons increases, so electrons are hold tightly to nucleus. Hence, removal of electron from outermost shell becomes difficult making the atom less metallic in nature.
Wavelength because it is shorter
It’s option B 0.0821L.atm/mol.K
Answer:
hydrocarbons are compounds which contains Hydrogen and carbon
The statement which is true about <em>Atom A</em> and <em>Atom B</em> is; Choice B: <em>Atom B will give up electrons to form bonds.</em>
According to the question;
For Atom A:
- the electron configuration is; <em>1s²2s²2p³</em>
- Therefore, it has 5 valence electrons.
For atom B:
- the electron configuration is; <em>1s²2s²2p⁶3s²3p¹</em>
- Therefore, it has 3 valence electrons.
Since, electrons need 8 electrons to assume a full octet;
Consequently, Atom B will give up electrons to become stable.
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