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Chemistry

1 answer:

xxMikexx [17]2 years ago

6 0

Answer:

3. It should restate the question

4. a controlled experiment

5. if I freeze a tennis ball then it will not bounce as high

Explanation:

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Compounds in a and b were named incorrectly. On a sheet of paper draw the molecule that fits the given description. From the str

krok68 [10]

Answer:

a. 4—ethyl—5—methyloctane

b. 2,2,6—trimethyloctane

Explanation:Please see attachment for explanation

3 0

3 years ago

4. What is the role of the benedict solution in testing for presence of carbohydrates

Vanyuwa [196]

Answer:

it identifies reducing sugars (monosaccharide's and some disaccharides), which have free ketone or aldehyde functional group

Explanation:

It turns from turquoise to yellow or orange when it reacts with reducing sugars.

3 0

3 years ago

How can electronegativity be used to explain the reaction we see in terms of the numbers and types of bonded being formed in lit

kolezko [41]

Explanation:

Lithium is an electropositive element that readily loses electrons.

Oxygen is electronegative and it will readily accept electrons.

Due to this significant electronegativity differences between the two species they form electrovalent or ionic bonds between them.

2atoms of Li lose two electrons:

Li → Li²⁺ + e⁻

Lithium isoelectronic with helium

For oxygen;

O + 2e⁻ → O²⁻

Oxygen is isoelectronic with Neon

Two ions of the lithium combines with the oxygen to form the bond;

4Li + O₂ → 2Li₂O

The electrostatic attraction between the two ions forms the ionic bond

5 0

3 years ago

Consider the following reaction between mercury(II) chloride and oxalate ion.

Alina [70]

Answer: The rate law of the reaction is $\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2$

Explanation:

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)$