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Lapatulllka [165]
3 years ago
14

Solve M=h-w/8 for the variable H

Mathematics
2 answers:
aliina [53]3 years ago
6 0

Answer:

Step-by-step explanation:

(1) M = h - \frac{w}{8}

    h = M + \frac{w}{8}

(2) M = h - \frac{w}{8}

    M - h = -\frac{w}{8}

    \frac{w}{8} = h - M

   w = 8(h - M)

(3) w = x + \frac{y}{z}

   (w-x) = \frac{y}{z}

   \frac{z}{y} = \frac{1}{(w-x)}

   z = \frac{y}{w-x}

(5) Area of triangle A = \frac{1}{2}b

    b = 2A

(6) P=\frac{kt}{v}

    ⇒ PV = kt

    ⇒ k = \frac{PV}{t}

ANTONII [103]3 years ago
5 0
1) m = h - w/8

Subtract h from both sides.

m - h = -w/8

Subtract m from both sides.

-h = -m - w/8

Divide all terms by -1.

h = m + w/8.

2) m = h - w/8

Get rid of the denominator 8 by multiplying 8/1 to all terms.

8m = 8h - w

Add w on both sides and subtract 8m from both sides.

w = 8h - 8m

3) w = x + y/z

Get rid of the denominator z by multiplying it to all terms.

wz = xz + y

Subtract xz from both sides of the equation.

wz - xz = y OR y = wz - xz

4) w = x + y/z

Subtract x from both sides.

w - x = y/z

Get rid of the denominator by multiplying it to all terms.

wz - xz = y

Now factor the expression wz - xz.

z(w - x) = y

Divide both sides by w - x.

z = y / w - x

This is read as z equals to y divided by w minus x.

5) The area of a triangle is A = 1/2bh

First, get rid of the denominator by multiplying both sides by 2.

2A = bh

To find b, divide both sides by h.

2A/h = b

6) P = kt/v

Multiply both sides by v.

Pv = kt

Divide both sides by t.

Pv/t = k OR k = Pv/t.
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