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3 years ago

6

What is 3x2/3=. Show work please

1 answer:

KatRina [158]3 years ago

7 0

If you're confused whether to do multiplication or division first.
<span>Remember PEMDAS. It's the Order of Operation. Basically, it's the order of which operators are prioritized in an equation.

From Highest to Lowest Priority.
Parentheses, Exponents, (Multiplication and Division), and (Addition and Subtraction)

Multiplication and Division have the same priority, as well as Addition and Subtraction.

So for this it is which ever comes first, from left to right of the equation is prioritized.

WORKING:

3x2/3

The multiplication operator comes first, so we do:
3 x 2=6

Finally, we take "6" and divide it by 3

6 / 3 = 2

Answer is: 2</span>

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3 years ago

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3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

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3 years ago

Read 2 more answers

Find BC :<br> I am having trouble finding can anyone help ?

Zina [86]

24 because 12 + 12 = 24 and and CD = DB

CB = CD + CB = 24 the triange ADC and ADB are equal

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3 years ago

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y = mx + b

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3 years ago