Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
The answer would be -5 1/4
Answer:
r = 49
Step-by-step explanation:
686 = 14r
686/14= 49
r = 49
Answer:
12 constant terms and 12 variable terms
Step-by-step explanation:
no, more than one triangle could be made with these measures
sss