of the class consists of freshmen.
Step-by-step explanation:
Given,
Total number of students = 40
Number of freshmen = 18
Number of sophomores = 19
Number of juniors = 3
Fraction of freshmen = 
Fraction of freshmen = 
Fraction of freshmen =
of the class consists of freshmen.
Keywords: fraction, division
Learn more about fractions at:
#LearnwithBrainly
12x+2=17y
12x+2=17(0)
12x+2=0
-2 -2
——
12x+0= -2
— —
12 12
x= -2/12
X= -1/6
Alright, so you have the basic formula- good.
You have the A value (400), the interest rate r (7.5% -> .075 in decimal), and the final P value (8500). So, we only need to solve for t.
8500 = (400)(1+.075)^t
/400 /400
21.25 = 1.075^t
logarithms are the inverse of exponents, basically, if you have an example like
y = b^x, then a logarithm inverts it, logy(baseb)=x
Makes sense if you consider a power of ten.
1000 = 10^3
if you put logbase10(1000), you'll get 3.
Anyways, though, to solve the problem make a log with a base of 1.075 in your calculator
log21.25(base 1.075) = t
also, because of rules of change of base (might want to look this up to clarify), you can write this as log(21.25)/log(1.075) = t
Thus, t is 42.26118551.
Rounded to hundredths, t=42.26
Answer:
Step-by-step explanation:
Numerator
sin
x
cos
y
+
cos
x
sin
y
−
[
sin
x
cos
y
−
cos
x
sin
y
)
=
sin
x
cos
y
+
cos
x
sin
y
−
sin
x
cos
y
+
cos
x
sin
y
=
2
cos
x
sin
y
Denominator
cos
x
cos
y
−
sin
x
sin
y
+
cos
x
cos
y
+
sin
x
sin
y
=
cos
x
cos
y
−
sin
x
sin
y
+
cos
x
cos
y
+
sin
x
sin
y
=
2
cos
x
cos
y
---------------------------------------------------------------
left side can now be expressed as
2
cos
x
sin
y
2
cos
x
cos
y
=
2
cos
x
sin
y
2
cos
x
cos
y
=
sin
y
cos
y
and
sin
y
cos
y
=
tan
y
=
right side hence proved
The empirical rule states that in a normal distribution,
68% of data is within 1 std deviation of the mean
95% of data is within 2 std deviation of the mean
99.7% of data is within 3 std deviation of the mean
In this case 95% of the cases would be within two std deviations of the mean
mean - 8 and mean + 8
72 - 8 = 64 and 72 + 8 = 80
then 95% of the scores are between 64% and 80% on the test.
