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2 years ago

What is the slope and y-Intercept of the equation 3(y – 2) + 6(x + 1) - 2 = 0?

Mathematics

2 answers:

aliina [53]2 years ago

5 0

⇒ 3(y - 2) + 6(x + 1) - 2 = 0

⇒ 3y - 6 + 6x + 6 - 2 = 0

⇒ 3y = -6x + 2

⇒ y = (-6x + 2)/3

⇒ y = -2x + ⅔

<h3>FINAL ANSWER :</h3>

Slope = -2

Y - intercept = +⅔

<h3>Answer :</h3>

Option (a) is the correct answer .

Ne4ueva [31]2 years ago

4 0

Answer:

A. Slope = -2, y-intercept = 2/3

Step-by-step explanation:

Convert the given equation into slope-intercept form:

3(y - 2) + 6(x + 1) - 2 = 0
3y - 6 + 6x + 6 - 2 = 0
3y + 6x - 2 = 0
3y = - 6x + 2
y = - 2x + 2/3

The slope is -2, the y-intercept is 2/3

Correct choice is A

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Find the least squares regression equation using the school year (in number of years after 2000) for the input variable and the

Ad libitum [116K]

Answer-

The least squares regression equation using the school year (in number of years after 2000) for the input variable and the average cost (in thousands of dollars) for the output variable is "y=0.937x+12.765" .

Solution-

The independent variable / input variable= x = Number of years after 2000 ( = year-2000)

The dependent variable / output variable = y = Average cost in thousands of dollars

(The table has been attached herewith.)

To find the regression equation for a group of (x,y) points,

We have to calculate the slope and y-intercept, then we can put those values in the equation y = mx + c ( Slope - Intercept formula)

We know that,

$Slope=m=\frac{N\sum xy -\sum x\sum y}{N\sum x^{2}- (\sum x)^{2}}$

Putting the values from the table,

$m=\frac{(8 \times 1020.206)-(52 \times 150.894)}{(8 \times 3810)-(52^2)}$

( ∵ Instead of 150,894 we have to put 150.894 as we have find the line for year and thousands of dollars )

$\Rightarrow m =\frac{8161.648-7846.488}{3040-2704} =\frac{315.16}{336}=0.937$

Now, for the y-intercept,

$c =\frac{\sum y -m(\sum x)}{N}$

Putting the values,

$c=\frac{150.894-(52 \times 0.937)}{8}=\frac{102.125}{8}=12.765$

Now, putting the values of c and m, in the Slope-Intercept formula,

$y=0.937x+12.765$

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3 years ago

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .

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Step-by-step explanation:

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saveliy_v [14]

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3 years ago

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