Answer:
720 possible ways
Step-by-step explanation:
The gold is awarded to the first position, the silver is awarded to the second position while the bronze is awarded to the third position.
The first position can be taken by any of the 10 runners
Now, the second position can be taken by remaining 9 runners
while the third position can be taken by the renaming 8 runners.
Thus, the number of ways in which these medals can be awarded = 10 * 9 * 8 = 720 ways
G = 1, 9.
There are two cases to this problem: G is either to the left or right of E. If G is to the left of E, then G = 5 - 4 = 1 and if G is to the right of E, then G = 5 + 4 = 9. Therefore, our answer is G = 1, 9.
6:5
because 30 and 36 can both be divided by 6;
36/6= 6
30/6= 5
so the ratio is 6 to 5
GCF OF 20 AND 32: 4
Gcf of 45 and 75: 15
GcF of 20 and 32
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 32: 1, 2, 4, 8, 16, 32
COMMON FACTORS: 1, 2, 4
GCF:4
Gcf of 45 and 75
Factors of 45: 15, 9, 5, 3, 1.
Factors of 75: 25, 15, 5, 3, 1.
CommoN factors: 1, 3, 5, 15
GCF:15
HOPE OT HELPED
D) x = -2/3 and x = 6
4(x²−x+2)−(x+10)(x+2) Distribute
(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20 Multiply
4x² + −4x + 8 + −x² + −12x + −20 Combine like terms
(4x² + −x²) + (−4x + −12x) + (8 + −20) Combine like terms
3x² −16x −12 = 0
x = -2/3 and x = 6
I graphed the equation on the graph below.
If this answer is correct, please make me Brainliest!
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