All categories

3 years ago

Help me please and explain. FIND THE AREA OF THE UNSHADED REGION

Mathematics

2 answers:

bagirrra123 [75]3 years ago

5 0

To solve this first find the area of each of the white shapes inside the rectangle

The formula for the area of a circle is:

A = πr²

In this case we know that the radius is 2

Plug what you know into the area of a circle formula:

A = π2²

A = π4

A = 4π

A ≈ 12.57

The formula for the area of a square is:

A = Length x Height

In this case we know that both length and height are 3

Plug what you know into the formula for area of a square:

A = 3 x 3

A = 9

To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):

12.57 + 9 ≈ 21.57

To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.

The formula for the area of a rectangle is:

A = Length x Height

The length is 10 and the height is 7

A = 10 x 7

A = 70

Shaded region:

70 - 21.57 = 48.43

Unshaded region: 21.57

Total area of surrounding rectangle: 70

Shaded region: 48.43

Hope this helped!

~Just a girl in love with Shawn Mendes

Inga [223]3 years ago

3 0

Answer:

A is 48cm squared

Step-by-step explanation:

firstly find the area of the unshaded parts:

area of circle A=3.142*2 squared

A=3.142 * 4

A=13cm squared. area of square A=L squared

A=3 squared

. A=9cm squared

then add the areas A=13+9

=22cm squared

Now area of the big rectangle

A=l*b

=7*10

=70cm squared

therefore subtract the area occupied by the unshaded parts from the area of the big shape.

You might be interested in

What angle do the minute and hour hands make at 4:30??

seraphim [82]

Answer:

45°

Step-by-step explanation:

The hour hand makes a trip of 360° around the face of the clock in 12 hours, so in 4.5 hours will make an angle of ...

... (4.5/12)·360° = 135°

clockwise from straight up.

The minute hand makes that 360° turn in 1 hour, so in 30 minutes, it will be 180° clockwise from straight up.

The difference between the angles of the hands is ...

... 180° -135° = 45°

3 0

3 years ago

Is 8π rational or irrational number?

evablogger [386]

Irrational i assume

3 0

3 years ago

Scale on a map is 1:800000. motorway is 120 km long . what distance will it be on the map

Rudik [331]

Answer:

Multiply the number of inches on the map times the scale to determine the true distance. For example, if the distance on the map was 5.5 inches and the scale was 1:6,336,000, the true distance would be 550 miles. To convert an area, convert the dimensions using the scale and then find the true area.

7 0

3 years ago

Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th

Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34$

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{990 - 975}{9.34}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463

X = 960

$Z = \frac{X - \mu}{s}$

$Z = \frac{960 - 975}{9.34}$

$Z = -1.61$

$Z = -1.61$ has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0

3 years ago

The elevation of lake sam rayburn is 164 above mean sea level during the summer if it does not rain the elevation of the lake de

andrew-mc [135]

Answer:

I guess that you want to model the elevation of Lake Sam Rayburn.

During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).

If it does not rain, the elevation of the lake decreases by 0.5ft each week.

So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.

L(w) = 165ft - 0.5ft*w

Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,

L(0) = 165ft - 0.

4 0

3 years ago

Help me please and explain. FIND THE AREA OF THE UNSHADED REGION ​

Help me please and explain. FIND THE AREA OF THE UNSHADED REGION