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Sveta_85 [38]
4 years ago
11

Can a triangle have sides of length 4,7,11?

Mathematics
1 answer:
Lesechka [4]4 years ago
6 0

Answer:

No because 16+49 does not equal 121.

Step-by-step explanation:

first make 11 the hypotenuse and 4 and 7 side b and A

Use the pythagorean theorem: A^2+B^2=C^2

4^2+7^2=11^2

16+49=121

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x = one odd number

the second odd number is (x+2), as both are consecutive.

so,

x × (x + 2) = 195

x² + 2x = 195

x² + 2x - 195 = 0

the formula to solve this is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -195

x = (-2 ± sqrt(4 - 4×1×-195))/(2×1) =

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x1 = -1 + 14 = 13

x2 = -1 - 14 = -15 which is invalid as the numbers are positive.

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for 2x+1=0
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so for this one you isolate for x and in order to get rid of 2x you divide by 2 for both
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